Optimal. Leaf size=88 \[ -\frac{\sqrt{1-2 x} (3 x+2)^3}{5 (5 x+3)}+\frac{21}{125} \sqrt{1-2 x} (3 x+2)^2-\frac{294}{625} \sqrt{1-2 x}-\frac{196 \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )}{625 \sqrt{55}} \]
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Rubi [A] time = 0.0268392, antiderivative size = 88, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {97, 153, 12, 80, 63, 206} \[ -\frac{\sqrt{1-2 x} (3 x+2)^3}{5 (5 x+3)}+\frac{21}{125} \sqrt{1-2 x} (3 x+2)^2-\frac{294}{625} \sqrt{1-2 x}-\frac{196 \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )}{625 \sqrt{55}} \]
Antiderivative was successfully verified.
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Rule 97
Rule 153
Rule 12
Rule 80
Rule 63
Rule 206
Rubi steps
\begin{align*} \int \frac{\sqrt{1-2 x} (2+3 x)^3}{(3+5 x)^2} \, dx &=-\frac{\sqrt{1-2 x} (2+3 x)^3}{5 (3+5 x)}+\frac{1}{5} \int \frac{(7-21 x) (2+3 x)^2}{\sqrt{1-2 x} (3+5 x)} \, dx\\ &=\frac{21}{125} \sqrt{1-2 x} (2+3 x)^2-\frac{\sqrt{1-2 x} (2+3 x)^3}{5 (3+5 x)}-\frac{1}{125} \int -\frac{98 (2+3 x)}{\sqrt{1-2 x} (3+5 x)} \, dx\\ &=\frac{21}{125} \sqrt{1-2 x} (2+3 x)^2-\frac{\sqrt{1-2 x} (2+3 x)^3}{5 (3+5 x)}+\frac{98}{125} \int \frac{2+3 x}{\sqrt{1-2 x} (3+5 x)} \, dx\\ &=-\frac{294}{625} \sqrt{1-2 x}+\frac{21}{125} \sqrt{1-2 x} (2+3 x)^2-\frac{\sqrt{1-2 x} (2+3 x)^3}{5 (3+5 x)}+\frac{98}{625} \int \frac{1}{\sqrt{1-2 x} (3+5 x)} \, dx\\ &=-\frac{294}{625} \sqrt{1-2 x}+\frac{21}{125} \sqrt{1-2 x} (2+3 x)^2-\frac{\sqrt{1-2 x} (2+3 x)^3}{5 (3+5 x)}-\frac{98}{625} \operatorname{Subst}\left (\int \frac{1}{\frac{11}{2}-\frac{5 x^2}{2}} \, dx,x,\sqrt{1-2 x}\right )\\ &=-\frac{294}{625} \sqrt{1-2 x}+\frac{21}{125} \sqrt{1-2 x} (2+3 x)^2-\frac{\sqrt{1-2 x} (2+3 x)^3}{5 (3+5 x)}-\frac{196 \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )}{625 \sqrt{55}}\\ \end{align*}
Mathematica [A] time = 0.0358821, size = 63, normalized size = 0.72 \[ \frac{\sqrt{1-2 x} \left (1350 x^3+2385 x^2-90 x-622\right )}{625 (5 x+3)}-\frac{196 \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )}{625 \sqrt{55}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.01, size = 63, normalized size = 0.7 \begin{align*}{\frac{27}{250} \left ( 1-2\,x \right ) ^{{\frac{5}{2}}}}-{\frac{117}{250} \left ( 1-2\,x \right ) ^{{\frac{3}{2}}}}+{\frac{18}{625}\sqrt{1-2\,x}}+{\frac{2}{3125}\sqrt{1-2\,x} \left ( -2\,x-{\frac{6}{5}} \right ) ^{-1}}-{\frac{196\,\sqrt{55}}{34375}{\it Artanh} \left ({\frac{\sqrt{55}}{11}\sqrt{1-2\,x}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 2.29583, size = 108, normalized size = 1.23 \begin{align*} \frac{27}{250} \,{\left (-2 \, x + 1\right )}^{\frac{5}{2}} - \frac{117}{250} \,{\left (-2 \, x + 1\right )}^{\frac{3}{2}} + \frac{98}{34375} \, \sqrt{55} \log \left (-\frac{\sqrt{55} - 5 \, \sqrt{-2 \, x + 1}}{\sqrt{55} + 5 \, \sqrt{-2 \, x + 1}}\right ) + \frac{18}{625} \, \sqrt{-2 \, x + 1} - \frac{\sqrt{-2 \, x + 1}}{625 \,{\left (5 \, x + 3\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.63244, size = 201, normalized size = 2.28 \begin{align*} \frac{98 \, \sqrt{55}{\left (5 \, x + 3\right )} \log \left (\frac{5 \, x + \sqrt{55} \sqrt{-2 \, x + 1} - 8}{5 \, x + 3}\right ) + 55 \,{\left (1350 \, x^{3} + 2385 \, x^{2} - 90 \, x - 622\right )} \sqrt{-2 \, x + 1}}{34375 \,{\left (5 \, x + 3\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 88.8946, size = 202, normalized size = 2.3 \begin{align*} \frac{27 \left (1 - 2 x\right )^{\frac{5}{2}}}{250} - \frac{117 \left (1 - 2 x\right )^{\frac{3}{2}}}{250} + \frac{18 \sqrt{1 - 2 x}}{625} - \frac{44 \left (\begin{cases} \frac{\sqrt{55} \left (- \frac{\log{\left (\frac{\sqrt{55} \sqrt{1 - 2 x}}{11} - 1 \right )}}{4} + \frac{\log{\left (\frac{\sqrt{55} \sqrt{1 - 2 x}}{11} + 1 \right )}}{4} - \frac{1}{4 \left (\frac{\sqrt{55} \sqrt{1 - 2 x}}{11} + 1\right )} - \frac{1}{4 \left (\frac{\sqrt{55} \sqrt{1 - 2 x}}{11} - 1\right )}\right )}{605} & \text{for}\: x \leq \frac{1}{2} \wedge x > - \frac{3}{5} \end{cases}\right )}{625} + \frac{194 \left (\begin{cases} - \frac{\sqrt{55} \operatorname{acoth}{\left (\frac{\sqrt{55} \sqrt{1 - 2 x}}{11} \right )}}{55} & \text{for}\: 2 x - 1 < - \frac{11}{5} \\- \frac{\sqrt{55} \operatorname{atanh}{\left (\frac{\sqrt{55} \sqrt{1 - 2 x}}{11} \right )}}{55} & \text{for}\: 2 x - 1 > - \frac{11}{5} \end{cases}\right )}{625} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 2.51324, size = 122, normalized size = 1.39 \begin{align*} \frac{27}{250} \,{\left (2 \, x - 1\right )}^{2} \sqrt{-2 \, x + 1} - \frac{117}{250} \,{\left (-2 \, x + 1\right )}^{\frac{3}{2}} + \frac{98}{34375} \, \sqrt{55} \log \left (\frac{{\left | -2 \, \sqrt{55} + 10 \, \sqrt{-2 \, x + 1} \right |}}{2 \,{\left (\sqrt{55} + 5 \, \sqrt{-2 \, x + 1}\right )}}\right ) + \frac{18}{625} \, \sqrt{-2 \, x + 1} - \frac{\sqrt{-2 \, x + 1}}{625 \,{\left (5 \, x + 3\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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